Questions
A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure.
The potential difference developed across the ring when its speed , is
detailed solution
Correct option is D
Motional emf induced in the semicircular ring PQR is equivalent to the motional emf induced in the imaginary conductor PR. i.e., εPQR=εPR=Bvl=Bv(2r) (l= PR = 2r)Therefore, potential difference developed across the ring is 2rBv with R is at highe rpotential.Talk to our academic expert!
Similar Questions
A conductor rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets
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