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Questions  

A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. 

The potential difference developed across the ring when its speed ν, is 
 

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a
zero
b
Bvπr22 and P is at higher potential
c
πrBν and R is a higher potential
d
2rBv and R is at higher potential
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detailed solution

Correct option is D

Motional emf induced in the semicircular ring PQR is equivalent to the motional emf induced in the imaginary conductor PR.  i.e., εPQR=εPR=Bvl=Bv(2r)                                   (l= PR = 2r)Therefore, potential difference developed across the ring is 2rBv with R is at highe rpotential.


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