Questions
A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure.
The potential difference developed across the ring when its speed , is
Unlock the full solution & master the concept.
Ready to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is D
Motional emf induced in the semicircular ring PQR is equivalent to the motional emf induced in the imaginary conductor PR. i.e., εPQR=εPR=Bvl=Bv(2r) (l= PR = 2r)Therefore, potential difference developed across the ring is 2rBv with R is at highe rpotential.
Similar Questions
A conductor rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets
Get your all doubts cleared from
Sri Chaitanya experts
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
