Questions
A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction B. At the position MNQ, the speed of the ring is v and the
potential difference developed across the ring is
detailed solution
Correct option is D
Rate of decrease of area of the semicircular ring −dAdt=(2R)vAccording to Faraday's law of induction induced emf e=−dφdt=−BdAdt=−B(2Rv)The induced current in the ring must generate magnetic field in the upward direction. Thus Q is at higher potentialTalk to our academic expert!
Similar Questions
A square wire loop, of side a has a long straight wire carrying a constant current i that passes through the centre of the loop and perpendicular to its plane as shown in Fig.
The current induced in the square loop is
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