Questions
A thin solid disc of mass 1 kg and radius 25 cm is rotating about its own geometrical axis AB with angular velocity 12 rad/s. A particle of mass 1 kg is gently attached to the rim of the disc. Then new angular velocity of the disc is
detailed solution
Correct option is B
Conserving angular momentum, (I1+I2)ω=I1.ω0⇒ω=ω0(1+I2I1)=R(1+1×25212×1×252) rads=4 radsTalk to our academic expert!
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A disc rotates freely with rotational kinetic energy E about a normal axis through centre. A ring having the same radius but double the mass of disc is now, gently placed on the disc. The new rotational kinetic energy of the system would be
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