A thin solid disc of mass 1 kg and radius 25 cm is rotating about its own geometrical axis AB with angular velocity 12 rad/s. A particle of mass 1 kg is gently attached to the rim of the disc. Then new angular velocity of the disc is

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6 rad/s

4 rad/s

3 rad/s

8 rad/s

answer is B.

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Detailed Solution

Conserving angular momentum, (I1+I2)ω=I1.ω0⇒ω=ω0(1+I2I1)=R(1+1×25212×1×252) rads=4 rads

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