First slide
Law of conservation of angular momentum
Question

A thin uniform circular disc of mass M and radius R is rotating in a horizontal plane about an axis passing through its centre and perpendicular to its plane with an angular velocity ω. Another disc of same dimensions but of mass 14M is placed gently on the first disc co-axially. The angular velocity of the system is

Moderate
Solution

I1=MR22 and I2=MR22+12M4R2=58MR2

By conservation of angular momentum,

Iω1=I2ω2ω2=I1I2ω1

=(1/2)MR2(5/8)MR2ωω2=45ω

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