Q.

A thin, uniform, circular ring is rolling down an inclined plane of inclination 30o without slipping. Its linear acceleration along the inclined plane will be

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a

g/2

b

g/3

c

g/4

d

5g/14

answer is C.

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Detailed Solution

Linear accelerationa=gsin⁡θ/1+k2/R2∴ a=gsin⁡301+R2/R2=g/22=g4
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A thin, uniform, circular ring is rolling down an inclined plane of inclination 30o without slipping. Its linear acceleration along the inclined plane will be