A thin uniform rod AB of mass $$m=1$$ kg moves translationally with acceleration a $$=$$ $$2$$ $$ms-2$$ due to two $$anti-parallel$$ forces $$F1$$ and $$F2$$. The distance between the points at which these forces are applied is equal to l $$=$$ $$20$$ cm. Besides, it is known that $$F2$$ $$=$$ $$5$$ N. Find the length of the rod, in metre.

Question

Infinity Learn · Accepted Answer

Let x be the distance of centre point C of rod from D. Then     $$F2$$−$$F1=ma$$⇒$$F1=3NFurther$$, τ$$c=0$$⇒ $$F2x=F1(0.2+x)$$⇒ $$5x=F1(0.2+x)$$⇒ $$5x=3(0.2+x)$$⇒ $$x=0.3mSo$$, length of rod is L $$=$$ $$2(x$$ $$+$$ $$0.2)$$ $$=$$ $$1$$ m

Q.

Unlock the Full Solution and Master the Concept