A thin uniform rod of mass ‘M’ and length ‘L' rotating about a perpendicular axis passing through its center with a constant angular velocity 'ω'.Two objects each of mass M3are attached gently to the two ends of the rod. The rod will now rotate with an angular velocity of :

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answer is 4.

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Detailed Solution

According To Law of Conservation of Angular Momentum. Li=LfML212 × ω = ML212 + 2M3L22ωf ω3=ωf

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