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Law of conservation of angular momentum

Question

A thin uniform rod of mass ‘M’ and length ‘L' rotating about a perpendicular axis passing through its center with a constant angular velocity 'ω'.Two objects each of mass M3are  attached gently to the two ends of the rod. The rod will now rotate with an angular velocity of  : 

Moderate
Solution

According To Law of Conservation of Angular Momentum.

                    Li=LfML212  ×  ω  =  ML212  +  2M3L22ωf                   ω3=ωf



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