A thin wire AB of length l and mass m is bent in the form of a semicircle as shown in fig. Its momentof inertia about an axis joining its free ends will be
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a
ml2
b
Zero
c
ml2/π2
d
ml2/2π2
answer is D.
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Detailed Solution
Here, πr=l or r=l/πThe moment of inertia of a ring about its diameter is given by I=12Mr2∴Moment of inertia of semicircle=12mlπ2=ml22π2
A thin wire AB of length l and mass m is bent in the form of a semicircle as shown in fig. Its momentof inertia about an axis joining its free ends will be