Questions
A thin wire of length L and uniform linear mass density p is bent into a circular loop with centre O as shown in fig. The moment of inertia of the loop about the axis XX' is
detailed solution
Correct option is D
The moment of inertia of the loop about the diameter = M R2/ 2. So, the moment of inertia of the loop about XX' is given byIXX=MR22+MR2=32MR2where M = mass of the loop and .R = radius of the loop NowM=Lρ and R=L/2π∴ IXX′=32(Lρ)(L/2π)2=3L3ρ/8π2Talk to our academic expert!
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The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid-point and perpendicular to its length is I0 , Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
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