A thin wire of length L and uniform linear mass density ρ is bent into a circular loop with centre at O as shown. The moment of inertia of the loop about the axis XX1 is
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a
ρL38π2
b
ρL316π2
c
5ρL316π2
d
3ρL38π2
answer is D.
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Detailed Solution
Mass per unit length of the wire =ρ Mass of L length, M=ρL and since the wire of length L is bent in a form of circular loop therefore 2πR=L⇒R=L2π Moment of inertia of loop about given axis =32MR2=32ρLL2π2=3ρL38π2