A thin wire of mass M and length L is turned into a ring. The moment of inertia about its will be :
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a
14π2ML2
b
112ML2
c
13π2ML2
d
1π2ML2
answer is A.
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Detailed Solution
When the wire is bend to form a circular ring, length of wire is same as circumference of ring, 2πR=LRadius of ring is R=L2πMoment of inertia of ring about its axis is given asI=MR2=ML2π2I=14π2ML2.