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Q.

A thin wire, suspended vertically from one end, is stretched by attaching weight of 20 N to the lower end. The weight stretches the wire by 1mm. How much elastic potential energy is stored in the wire?

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a

0.01 J

b

0.02 J

c

0.04 J

d

1.0 J

answer is A.

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Detailed Solution

Energy =12Fe=122v×10−3=10−2J=0.01J
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