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Q.

A thin-walled pipe rolls along the floor. What is the ratio of its translational kinetic energy to its rotational kinetic energy about the central axis parallel to its length?

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a

1

b

32

c

23

d

43

answer is A.

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Detailed Solution

The rotational kinetic energy is K = 12Iω2, where I = mR2 is its rotational inertia about the centre of mass the ratio isKtransl Krot = 12mvcom212(mR2)(vcomR)2 = 1.00.
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