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Q.

The third line of Balmer series of an ion equivalent to hydrogen atom has wavelength of 108.5 nm. The ground state energy of an electron of this ion will be

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a

3.4 eV

b

13.6 eV

c

54.4 eV

d

122.4 eV

answer is C.

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Detailed Solution

For third line of Balmer series n1=2 n2=5∴1λ=RZ21n12-1n22 gives Z2=n12n22(n22-n12)λROn putting values Z = 2From E=-13.6Z2n2=-13.6(2)2(1)2=-54.4 eV
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