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Three bars each of area of cross - section A and length L are connected in series. The thermal conductivities of their materials are K, 2K, 1.5 K. If the temperatures of the external ends of the first and last bar are 200°C & 18°C, then the temperatures of both the junctions are

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a

T1=116°C,T2=74°C

b

T1=120°C,T2=84°C

c

T1=132°C,T2=98°C

d

T1=164°C,T2=62°C

answer is A.

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Detailed Solution

Q=KA(200−T1)L=(2 K)A(T1−T2)L=(1.5 K)A(T2−18)L⇒200−T1=2 T1−2 T2=1.5 T2−27 Solving T1=116°C and T2=74°C

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