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Q.

Three blocks are placed on smooth horizontal surface and lie on same horizontal straight line. Block 1 and block 3 have mass m each and block 2 has mass M (M > m). Block 2 and block 3 are initially stationary, while block 1 is initially moving towards block 2 with speed v as shown. Assume that all collisions are head on and perfectly elastic. What value of M/m ensures that block 1 and block 3 have the same final speed?

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a

5+2

b

5−2

c

2+5

d

3+5

answer is C.

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Detailed Solution

Let v1, v2 and v3 be velocities of blocks 1, 2 and 3 after suffering collision each. mv=mv1+Mv2 and v1−v2=−vSolving, we get v1=m−Mm+M<0∴ m
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