Three blocks are placed on smooth horizontal surface and lie on same horizontal straight line. Block 1 and block 3 have mass m each and block 2 has mass M (M > m). Block 2 and block 3 are initially stationary, while block 1 is initially moving towards block 2 with speed v as shown. Assume that all collisions are head on and perfectly elastic. What value of M/m ensures that block 1 and block 3 have the same final speed?
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a
5+2
b
5−2
c
2+5
d
3+5
answer is C.
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Detailed Solution
Let v1, v2 and v3 be velocities of blocks 1, 2 and 3 after suffering collision each. mv=mv1+Mv2 and v1−v2=−vSolving, we get v1=m−Mm+M<0∴ m