Three blocks A, B and C of masses 4 kg, 2 kg and I kg respectively are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and.B is
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a
2 N
b
6 N
c
8 N
d
18 N
answer is B.
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Detailed Solution
Acceleration of system of blocks isa = FmA+mB+mC = 144+2+1 = 2 m/s2Taking the blocks B and C as system N = (mB+mC) = (2+1)×2 = 6 N