Questions
Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively are in contact on a frictionless surface as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is
detailed solution
Correct option is B
Given, m A = 4kg, mB = 2kg and m C = 1kgSo, total mass, M = 4 + 2 + 1 = 7 kgNow, F = Ma ⇒ 14 = 7a ⇒ a = 2ms-2FBD of block A ,F - F' = 4a ⇒ F' = 14 - 4 × 2 ⇒ F' = 6 NHence, the contact force between A and B is 6N.Talk to our academic expert!
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Three identical blocks of masses m = 2 kg are drawn by a force 10.2 N on a frictionless surface. What is the tension (in newton) in the string between the blocks B and C?
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