Question

Three bodies are lying on a frictionless horizontal table and these are connected as shown in the figure. They are pulled towards right with a force T₃ = 60N If m₁ , m₂ and m₃ are equal to 10 kg,20kg and 30kg respectively, then the values of T₁ and T₂ will be

Easy

Solution

T₃ - T₂ = m₃a , T₂ - T₁ = m₁a, $a = \frac{T_{3}}{m_{1} + m_{2} + m_{3}}$

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