Three charge +q, +q and –q are situated in x-y plane at the point (0 , a) (0 , 0) (0 , –a). Then, the electric potential at a point in first quadrant whose position vector makes an angle θ with y axis and at a distance r(r>>a) from the origin is
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a
qacosθ2π∈0r2
b
q4π∈0r1+2acosθr
c
q4π∈0r
d
q4π∈0r1−2acosθr
answer is B.
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Detailed Solution
Potential at the point = potential due to the charge at the origin =potential due to the dipole =q4π∈0r+14πε0(2aq)cosθr2s