Three charges are placed at the vertices of an equilateral triangle of side ‘a’ as shown in the following figure. The force experienced by the charge placed at the vertex A in a direction normal to BC is
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a
Q2/4πε0a2
b
−Q2/4πε0a2
c
Zero
d
Q2/2πε0a2
answer is C.
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Detailed Solution
FB→=FC→=k⋅Q2a2Hence force experienced by the charge at A in the direction normal to BC is zero.