Three charges are placed at the vertices of an equilateral triangle of side ‘a’ as shown in the following figure. The force experienced by the charge placed at the vertex A in a direction normal to BC is

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Q2/4πε0a2

−Q2/4πε0a2

Zero

Q2/2πε0a2

answer is C.

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Detailed Solution

FB→=FC→=k⋅Q2a2Hence force experienced by the charge at A in the direction normal to BC is zero.

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