First slide

Electrostatic force

Question

Three charges $+ Q, q, + Q$ are placed respectively at a distance $O, (\frac{d}{2})$ and $(d)$ from the origin. If the net force experienced by $+ Q$ , placed at $x = 0$ , is zero then the value of $q$ is

NA

Solution

For equilibrium ${\vec{F}}_{A} + {\vec{F}}_{B} = O$
${\vec{F}}_{A} = {\vec{- F}}_{B} \frac{K Q Q}{d^{2}} = \frac{- K Q q}{{(d / 2)}^{2}} \frac{Q}{d^{2}} = \frac{- q (4)}{d^{2}} q = - \frac{Q}{4}$

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