Three charges Q, + q and +q are placed at the vertices of a right-angled isosceles triangle as shown. The net electrostatic energy of the configuration is zero if Q is equal to
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a
−q1+2
b
−2q2+2
c
−2q
d
+q
answer is B.
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Detailed Solution
Net electrostatic energy U=kQqa+kq2a+kQqa2=0⇒kqaQ+q+Q2=0⇒Q=−2q2+2