Q.
Three charges Q, (+q) and (+q) are placed at the vertices of an equilateral triangle of side I as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to
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a
-q2
b
-q
c
+q
d
Zero
answer is A.
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Detailed Solution
Potential energy of the system,U=kQql+kq2l+kqQl=0 ⇒kql(Q+q+Q)=0⇒Q=-q2
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