Three charges Q , +q and +q are placed at the vertices of a right angled isosceles triangle as shown The electrostatic energy of the configuration is zero if Q is equal to

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−q1+2

−2q2+2

−2q

answer is B.

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Detailed Solution

Net electrostatic energy should be zero.U=kQqa+kq2a+kQqa2=0⇒kqaQ+q+Q2=0 ⇒Q+q+Q2=0 ⇒Q1+12=-q ⇒Q2+12=-q⇒Q=-q21+2=-q21+222 ⇒Q=−2q2+2

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