Three closed vessels A, B and C are at the same temperature T and contain gases which obey the Maxwellian distribution of velocities. Vessel A contains only $$02$$, B only $$N2$$ and C a mixture of equal quantities of $$02$$ and $$N2$$. If the average speed of the $$O2$$ molecules in vessel A is $$V1$$ that of the $$N2$$ molecules in vessel B is $$V2$$ the average speed of the $$O2$$ molecules in vessel C is (where$$ M is the mass of an oxygen $$molecule)

Question

Three closed vessels A, B and C are at the same temperature T and contain gases which obey the Maxwellian distribution of velocities. Vessel A contains only $$02$$, B only $$N2$$ and C a mixture of equal quantities of $$02$$ and $$N2$$. If the average speed of the $$O2$$ molecules in vessel A is $$V1$$ that of the $$N2$$ molecules in vessel B is $$V2$$ the average speed of the $$O2$$ molecules in vessel C is (where$$ M is the mass of an oxygen $$molecule)

Infinity Learn · Accepted Answer

Average speed of gas molecule vav $$=$$ $$8kT$$$$π$$m. It depends on temperature and molecular mass. So the average speed of oxygen will be same in vessel A and vessel C and that is equal to $$V1$$.

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