Three containers C1,C2 and C3 have water at different temperatures. The table below shows the final temperature T when different amounts of water (given in liters) are taken from each container and mixed (assume no loss of heat during the process)The value of θ (in 0C to the nearest integer) is -----------
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 0050.00.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
First Mixing : 1s θ1−60+2sθ2−60+0sθ3−60=0⇒θ1+2θ2=180 …………. 1 Second Mixing : 0s θ1−30+1sθ2−30+2sθ3−30=0⇒θ2+2θ3=90 …………. 2 Third mixing : 2s θ1−60+0sθ2−60+1sθ3−60=0⇒2θ1+θ3=180 …………. 3 Solving equations 1 2 and 3 we get θ1=80, θ2=50, θ3=20 Fourth mixing : 1s θ1−θ+1sθ2−θ+1sθ3−θ=0 ⇒80−θ+50−θ+20−θ=0 ⇒θ=1503=50