Three discs A, B and C having radii 2 m, 4 m and 6 m respectively are coated with carbon black on their outer surfaces. The wavelengths corresponding to maximum intensity are 300 nm, 400 nm and 500 nm respectively. The power radiated by them are QA,QB and QC respectively.
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a
QA is maximum
b
QB is maximum
c
QC is maximum
d
QA = QB = QC
answer is B.
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Detailed Solution
Q=σAT4⋅ Here A=πr2According to Wien's law λmT=bor T=b/λm Q=σπr2b/λm4or Q∝r2/λm4 ∴ QB>QC>QA