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Questions  

Three discs A, B and C having radii 2m, 4m, and 6 m respectively are coated with carbon black on their other surfaces. The wavelengths corresponding to maximum intensity are 300 nm, 400 nm and 500 nm, respectively. The power radiated by them are Qa, Qb and Qc respectively

a
Qa is maximum
b
Qb is maximum
c
Qc  is maximum
d
Qa = Qb = Qc

detailed solution

Correct option is B

Radiated power P = A∈σT4  ⇒ P ∝ AT4From Weins's law,  λmT = constant ⇒ T ∝ 1λm∴  P   ∝ A(λm)4∝r2(λm)4⇒ Qa:Qb:Qc = 22(300)4:42(400)4:62(500)4 ∴ Qb will be maximum

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