Three electric dipoles $\overrightarrow{{\mathrm{p}}_1}, \overrightarrow{{\mathrm{p}}_2 } \mathrm{and} \overrightarrow{{\mathrm{p}}_3}$ are placed along three sides of on equilateral triangle ABC as shown in figure If $\left|\overrightarrow{{\mathrm{p}}_1}\right|= \left|\overrightarrow{{\mathrm{p}}_2 }\right| = \left|\overrightarrow{{\mathrm{p}}_3}\right|=\mathrm{p}$and the dipole $\left|\overrightarrow{{\mathrm{p}}_3}\right|$ is removed from the system, then the resultant dipole moment of the system will be

• A

  $\sqrt{3}\mathrm{p}$

• B

  $\left(1+\sqrt{2}\right)\mathrm{p}$

• C

  $\sqrt{2}\mathrm{p}$

• D

  p