First slide

Electrostatic force

Question

Three equal charges are placed on the three corners of a square. If the force between q₁ and q₂ is F₁₂ and that between q₁ and q₃ is F₁₃, the ratio of magnitudes $\frac{F_{12}}{F_{13}}$ is

Easy

A

$1 / 2$
B

2
C

$1 / \sqrt{2}$
D

$\sqrt{2}$

Solution

$F_{12} = \frac{1}{4 {πε}_{0}} \cdot \frac{q^{2}}{a^{2}} and F_{13} = \frac{1}{4 {πε}_{0}} \cdot \frac{q^{2}}{(a \sqrt{2})^{2}} \Rightarrow \frac{F_{12}}{F_{13}} = 2$

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