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Q.

Three equal masses of ‘m’ kg are fixed at the vertices of an equilateral triangle ABC. The force acting on mass ‘2m’ kg placed at the centroid of  triangle is

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a

Gm23a2

b

32Gm2a2

c

zero

d

3Gm2x2

answer is C.

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Detailed Solution

Force of attraction between two masses=GMmr2;universal gravitation constant=G; mass=m; distance=r; F1=F2=F3=Gm2mAD2 ∴AD=CD=BD three equal forces of same magnitude acting on a point with θ=1200 angle  between any two adjacent forces lying in a plane then resultant force= 0
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Three equal masses of ‘m’ kg are fixed at the vertices of an equilateral triangle ABC. The force acting on mass ‘2m’ kg placed at the centroid of  triangle is