Three equal masses of ‘m’ kg are fixed at the vertices of an equilateral triangle ABC. The force acting on mass ‘2m’ kg placed at the centroid of triangle is
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a
Gm23a2
b
32Gm2a2
c
zero
d
3Gm2x2
answer is C.
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Detailed Solution
Force of attraction between two masses=GMmr2;universal gravitation constant=G; mass=m; distance=r; F1=F2=F3=Gm2mAD2 ∴AD=CD=BD three equal forces of same magnitude acting on a point with θ=1200 angle between any two adjacent forces lying in a plane then resultant force= 0
Three equal masses of ‘m’ kg are fixed at the vertices of an equilateral triangle ABC. The force acting on mass ‘2m’ kg placed at the centroid of triangle is