Three equal resistances each of 10Ω  are connected as shown in the fig. The maximum power consumedby each resistor is 20 W. Then maximum power consumed by the combination is

We know thatPp=P1+P2  and  Ps=P1P2P1+P2Resistances R1 and R2, are connected in parallel. Hence their equivalent power is (20 + 20) = 40 W. Now R3  is it in series and hencePs=20×4020+40=80060=13⋅3W