Three equal resistances each of R ohm are connected as shown in fig. A battery of 2 V and internal resistance 0 .1 ohm is connected across the circuit.The value of R for which the heat generated in the circuit will be maximum is

The three resistances are connected in parallel across the source. Their equivalent resistanceR′=R3Current in the circuit, i=2R′+0⋅1Heat produced, H = i2 R' = 4R′R′+0⋅12Heat will be maximum when dHdR′=0Thus ddR′4R′R′+0⋅12=0Solving, we get R = 0⋅1Ω∴ R = 3R' = 3 x 0.1= 0.3Ω