Three equal resistors connected in series across a source of e.m.f. together dissipate 10 watts of power. What would be power dissipated if the same resistors are connected in parallel across the same source of e.m.f.
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a
9 watts
b
90 watts
c
10 watts
d
100 watts
answer is B.
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Detailed Solution
We know that P=V2/RWhen resistances are connected in series, then R = 3RWhen resistances are connected in parellel, thenR2=R/3∴ 10=V23R and P=V2(R/3)=3V2Ror P10=9 or P=90 watt