First slide
Connected bodies
Question

Three equal weights A, B, C of mass 2 kg each are hanging on a string passing over a fixed frictionless pulley as shown in the fig. (3). The tension in the string connecting weights B and C is

Easy
Solution

T -2 g =2 a        For A ... (1)

T1 + 2g-T=2a    For B ...(2)

2g -T1 =2 a       For C ...(3)

Adding eqs. (1) and (2), we get 

T1 = 4a                      …(4)

From eqs. (3) and (4), 

2g - 4a = 2a or a=(g/3) ...(5)

Substituting the value of a from eq. (5) in eq. (4), we get

T1 =4 x (g/3) =13N

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App