Questions
Three forces 9 N, 12 N and 15 N acting at a point are in equilibrium. The angle between 9 N and 15 N is
a
cos−1(4/5)
b
cos−1(3/5)
c
π−cos−1(3/5)
d
π−cos−1(4/5)
detailed solution
Correct option is C
We can see that (9)2+(12)2=152 So, forces 9 and 12 are perpendicular to each other. tanα=129=43sinα=4/5 Angle between 9N and 15N is π−α=π−cos−1(3/5)Talk to our academic expert!
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Three forces 9 N, 12 N and 15 N acting at a point are in equilibrium the angle between 9 N and 15 N is
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