Three forces 202N,202N and 40N are acting along X, Y and Z – axis respectively on a 82kg mass at rest at origin. The magnitude of its displacement after 5s is,

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50m

25m

60m

62.5m

answer is D.

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Detailed Solution

u=0, F¯R=202i+202j+40k a=FR¯m=2022+202+40282=40282 ∵m=82 =5ms−2s=ut+12at2=0+12×5×52=62.5m

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