Three identical blocks of masses m $$=$$ $$2$$ kg are drawn by a force $$10.2$$ N on a frictionless surface. What is the tension (in$$ $$newton) in the string between the blocks B and C?

Question

Infinity Learn · Accepted Answer

Given, $$m1=m2=m3=2$$ kg,$$F=10.2$$ NThe FBD of given system is as shown belowFor body A, F $$-$$ $$T1$$ $$=$$ ma         ......(i)For$$ body B,  $$T1$$ $$-$$ T $$=$$ ma         ......$$(ii)For$$ body C,  T $$=$$ ma         ......$$(iii)Adding$$ Eqs. $$(i), (ii) and (iii), we $$getF=3ma$$⇒$$a=10.23$$×$$2=1.7$$ $$ms-2Alternately$$ Acceleration can be found as net acceleration of a system, i.e.$$a=$$ Total net force  Total mass $$=10.2(2+2+2)=10.26=1.7$$ $$ms-2So$$, net tension in string between the blocks B and C isT $$=$$ m × a $$=$$ $$2$$ × $$1.7$$ $$=$$ $$3.4$$ N

Three identical blocks of masses m = 2 kg are drawn by a force 10.2 N on a frictionless surface. What is the tension (in newton) in the string between the blocks B and C?

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