Questions
Three identical bodies of equal mass m each moves along a circle of radius .R under the action of their mutual gravitational attraction. The speed of each body is
detailed solution
Correct option is A
Due to mutual attraction, let every body is moving with a velocity v.From figure, AD=32Ror Lsin60∘=32R or L=32R×23=3RCentripetal force on an one mass M is2GM2L2cos60∘/2=Mv2R2GM2L2×32=Mv2R or GM(3R)2×3=v2R∴ V=GM3RTalk to our academic expert!
Similar Questions
Two particles each of mass m are placed at points A and C such that AB =BC =L as shown in fig.
The gravitational force on a third particle placed at D at a distance I metre on the perpendicular bisector of the line AC, is
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