Three identical bulbs B1,B2 and B3 are connected as shown in the figure. Total power consumed by the circuit is ‘p’. If the bulb B2 is fused, total power consumed by the system will be P1. Then

If resistance of each bulb is R, then initial equivalent resistance of the system is, RC=R×RR+R+R=3R/2.Write B2 gets fused, RC1=R+R=2RSince power consumed by the system=V2RCWe can write, P1P=RCRC1=3R/22R=34⇒P1=3P4