Q.

Three identical dipoles are arranged as shown below. What will be the net electric field at Pk=14πε0?

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a

k⋅px3

b

2kpx3

c

zero

d

2kpx3

answer is C.

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Detailed Solution

Point P lies at equatorial positions of dipole 1 and 2 and axial position of dipole 3.due to dipoles 1E1=k.px3 (towards left) due to dipole 2E2=k⋅px3 (towards left) due to dipole 3E3=k⋅(2p)x3 (towards right)  Net electric field=E1+E2-E3=k⋅(p)x3+k⋅(p)x3-k⋅(2p)x3=0So net field at P will be zero.
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