Three identical dipoles are arranged as shown below. What will be the net electric field at Pk=14πε0?

Point P lies at equatorial positions of dipole 1 and 2 and axial position of dipole 3.due to dipoles 1E1=k.px3 (towards left) due to dipole 2E2=k⋅px3 (towards left) due to dipole 3E3=k⋅(2p)x3 (towards right)  Net electric field=E1+E2-E3=k⋅(p)x3+k⋅(p)x3-k⋅(2p)x3=0So net field at P will be zero.