Three identical dipoles are arranged as shown below. What  will be the net electric field at Pk=14πε0?

Point P lies at equatorial positions of dipole 1 and 2 and axial position of dipole 3.Let dipole moment,  p2=p3=QL=p and p1=8QL=8pHence, field at Pdue to dipoles 1E1=k⋅8p2x3=k⋅px3( towards left )due to dipole 2E2=k⋅px2 (towards left) due to dipole 3E3=k⋅(2p)x3 (towards right) So net field at P will be zero.