First slide
Motion of centre of mass
Question

Three identical masses are kept at the corners of an equilateral triangle ABC under the action of mutual force of attraction, A moves towards B with a speed V, B moves towards C with speed V, and C moves towards A with same speed V. Then the speed of centre of mass of the system of particles is

Easy
Solution

No external force acting on the system is zero. Hence acceleration of centre of mass of the system is zero. Therefore Vc = 0.

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