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Q.

Three identical masses are kept at the corners of an equilateral triangle ABC under the action of mutual force of attraction, A moves towards B with a speed V, B moves towards C with speed V, and C moves towards A with same speed V. Then the speed of centre of mass of the system of particles is

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a

V

b

zero

c

3V

d

V/3

answer is E.

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Detailed Solution

No external force acting on the system is zero. Hence acceleration of centre of mass of the system is zero. Therefore Vc = 0.
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Three identical masses are kept at the corners of an equilateral triangle ABC under the action of mutual force of attraction, A moves towards B with a speed V, B moves towards C with speed V, and C moves towards A with same speed V. Then the speed of centre of mass of the system of particles is