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Three identical masses are kept at the corners of an equilateral triangle ABC under the action of mutual force of attraction, A moves towards B with a speed V, B moves towards C with speed V, and C moves towards A with same speed V. Then the speed of centre of mass of the system of particles is

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By Expert Faculty of Sri Chaitanya
a
V
b
zero
c
3V
d
V/3

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detailed solution

Correct option is E

No external force acting on the system is zero. Hence acceleration of centre of mass of the system is zero. Therefore Vc = 0.


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