Three identical particle with velocities v0i^,−3v0j^ and 5v0k^ collide successively with each other in such a way that they form a single particle. The velocity vector of resultant particle is
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a
v03(i^+j^+k^)
b
v03(i^−j^+k^)
c
v03(i^−3j^+k^)
d
v03(i^−3j^+5k^)
answer is D.
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Detailed Solution
from principle of conservation of linear momentumP→initial=P→final∴m(v0i^)+m(−3v0j^)+m(5v0k^)=3mv→ ∴v→=v03(i^−3j^+5k^)