First slide

Location of centre on mass for multiple point masses

Question

Three identical particles each of mass 1 kg are placed touching each other with their centers on a straight line. their centers are marked A. B and C respectively. The distance of center of mass of the system from A is

Easy

A

$\frac{AB + AC + BC}{3}$
B

$\frac{AB + AC}{3}$
C

$\frac{AB + BC}{3}$
D

$\frac{AC + BC}{3}$

Solution

$R_{CM} = \frac{1 \times 0 + 1 \times AB + 1 \times AC}{1 + 1 + 1} = \frac{AB + AC}{3}$

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