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Q.

Three identical particles each of mass 1 kg are placed with their centres on a straight line. Their centres are marked A, B and C respectively. The distance of centre of mass of the system from A is

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a

AB+AC+BC3

b

AB+AC3

c

AB+AC4

d

AB+BC3

answer is B.

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Detailed Solution

m1 = m2 = m3 = 1 kgxcm = m1x1+m2x2+m3x3m1+m2+m3=AB+AC3where x1= 0, x2 = AB, x3 = AC
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