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Three identical particles each of mass 1 kg are placed with their centres on a straight line. Their centres are marked A, B and C respectively. The distance of centre of mass of the system from A is

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By Expert Faculty of Sri Chaitanya
a
AB+AC+BC3
b
AB+AC3
c
AB+AC4
d
AB+BC3

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detailed solution

Correct option is B

m1 = m2 = m3 = 1 kgxcm = m1x1+m2x2+m3x3m1+m2+m3=AB+AC3where x1= 0, x2 = AB, x3 = AC


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