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Q.

Three identical particles moving with velocities  v0i^-3v0j^ and 5v0k^ collide successively with each other in such a way that they form a single particle. The velocity of resultant particle in i^, j^, k^ form is

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a

v0i^-3j^+ 5k^

b

v03i^-3j^+ 5k^

c

v02i^-3j^+ 5k^

d

v03i^+3j^+ 5k^

answer is B.

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Detailed Solution

mv0i¯-3mV0j¯+5mv0k¯=m+m+mv ∴v=mv0i^-3j^+5k^3m
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