First slide

Universal law of gravitation

Question

Three identical point masses, each of mass 1 kg lie in the XY plane at points (0,0) , (0,0.2m) and (0.2m,0). The net gravitational force on the mass at the origin is

Easy

A

$1.67 \times 10^{- 9} (\hat{j} + \hat{i})$
B

$3.34 \times 10^{- 10} (\hat{j} + \hat{i})$
C

$1.67 \times 10^{- 9} (\hat{i} - \hat{j})$
D

$3.34 \times 10^{- 10} (\hat{i} - \hat{j})$

Solution

${\vec{F}}_{A B} = \frac{G M_{A} M_{B}}{{r^{2}}_{A B}} \hat{j} = 1.67 \times 10^{- 9} \hat{j} N$
${\vec{F}}_{B C} = \frac{G M_{B} M_{c}}{{r^{2}}_{B C}} \hat{i} = 1.67 \times 10^{- 9} \hat{i} N$
${\vec{F}}_{n e t} = 1.67 \times 10^{- 9} (i + j) N$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App