Three identical spheres A, B and C of radius r and each carrying charge q are placed on the vertices of an equilateral triangle of side ll>>r The resultant force on B is F. Now an uncharged identical sphere is first touched with A and then with B and then removed. Now the resultant force on B is:
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a
F
b
218F
c
387F
d
274F
answer is B.
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Detailed Solution
F=F02+F02+2F0F0cos600=3F0=3Kq2l2Charges on the sphere after removal of sphereF'=Kq2l2382+342+3834=378Kq2l2=378×F3=218F